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2y^2-y=9
We move all terms to the left:
2y^2-y-(9)=0
We add all the numbers together, and all the variables
2y^2-1y-9=0
a = 2; b = -1; c = -9;
Δ = b2-4ac
Δ = -12-4·2·(-9)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{73}}{2*2}=\frac{1-\sqrt{73}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{73}}{2*2}=\frac{1+\sqrt{73}}{4} $
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